a^2=525

Solution for a^2=525 equation:

a^2=525

We move all terms to the left:

a^2-(525)=0

a = 1; b = 0; c = -525;
Δ = b2-4ac
Δ = 02-4·1·(-525)
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{21}}{2*1}=\frac{0-10\sqrt{21}}{2}
=-\frac{10\sqrt{21}}{2}
=-5\sqrt{21}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{21}}{2*1}=\frac{0+10\sqrt{21}}{2}
=\frac{10\sqrt{21}}{2}
=5\sqrt{21}
$